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Structural reference

Beam Load Calculator

Turn a span and a load into the maximum moment, deflection and the section modulus a beam needs.

Short answerFor a simply supported beam: uniform load M = wL² ÷ 8; center point load M = PL ÷ 4. Required section modulus S = M ÷ Fb. Check deflection (uniform) δ = 5wL⁴ ÷ (384 EI).

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How it's calculated

Bending moment sets the stress a beam must resist; the section modulus needed equals the moment divided by the allowable bending stress. Deflection is a separate serviceability check that depends on the moment of inertia and the modulus of elasticity. The formulas below cover the two most common simply supported cases.

UDL: M = wL²/8, δ = 5wL⁴/(384EI) Center point: M = PL/4 Required S = M ÷ Fb
Worked example
  1. L = 20 ft, w = 500 lb/ft (UDL).
  2. M = 500 × 20² ÷ 8 = 25,000 lb·ft.
  3. S = 300,000 ÷ 24,000 = 12.5 in³.

Reference tables

Simply supported beam — max values

LoadMax momentMax deflection
Uniform wwL²/85wL⁴/(384EI)
Center point PPL/4PL³/(48EI)
Two 1/3-point PPL/3

A number the tables do not give: a 20 ft simple span at 500 lb/ft needs about a 12.5 in³ section modulus at 24 ksi allowable — roughly a W8×15.

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FAQ

Simply supported or fixed?

These formulas are for simply supported (pinned) ends. Fixed or continuous beams have lower mid-span moments and need different coefficients.

Stress or deflection — which governs?

Either can. Long, lightly loaded beams are often deflection-governed; short, heavily loaded ones are stress-governed. Check both.

What allowable stress do I use?

Fb depends on material and code (e.g., ~0.66Fy for compact steel in ASD). Use the value from AISC/NDS for your member.

Does this replace an engineer?

No — it gives first-pass demand. Real beam design covers lateral-torsional buckling, connections and load combinations under a licensed engineer.

This page is a reference aid. Always verify against the AISC/NDS design standards and a licensed engineer. Figures shown are for orientation, not a stamped design.

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